A penetration tester conducted a discovery scan that generated the following:
 
Which of the following commands generated the results above and will transform them into a list of active hosts for further analysis?

A. nmap –oG list.txt 192.168.0.1-254 | sort

B. nmap –sn 192.168.0.1-254 | grep “Nmap scan” | awk ‘{print $5}’

C. nmap ––open 192.168.0.1-254 | uniq | sed ‘s/Nmap//2’ > file.txt

D. nmap –O 192.168.0.1-254 | cut –f








 

Suggested Answer: B

Community Answer: B



This question is in PT0-002 CompTIA PenTest+ Exam
For getting CompTIA PenTest+ Certificate


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